Set InitialDirectory : Open File Dialog « GUI Windows Form « C# / C Sharp

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C# / C Sharp » GUI Windows Form » Open File Dialog Screenshots  Set InitialDirectory   using System; using System.Windows.Forms; class MainClass {     static void Main(string[] args) {         OpenFileDialog dlg = new OpenFileDialog();         dlg.InitialDirectory = Application.StartupPath;         if (dlg.ShowDialog() == DialogResult.OK) {             Console.WriteLine(dlg.FileName);         }     } }   Related examples in the same category 1. Call ShowDialog() to display an OpenFileDialog 2. Set CheckFileExists to true 3. Set Filter 4. FileOk Action 5. shows browsing for a set of files 6. shows browsing for a file 7. Open File Dialog with file types 8. Demonstrates using an OpenFileDialog to prompt for a file name, and to open a file 9. Show the use of some of the OpenFile dialog box