Pattern Matching: beginning with 'b' : Regular Expression « String « SQL / MySQL

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SQL / MySQL » String » Regular Expression 
Pattern Matching: beginning with 'b'

/*

mysql> select * from Bird;
+----------+-------+---------+------+------------+------------+
| name     | owner | species | sex  | birth      | death      |
+----------+-------+---------+------+------------+------------+
| BlueBird | Joe   | Car     | f    | 1999-03-30 | NULL       |
| RedBird  | Yin   | Bus     | m    | 1979-04-30 | 0000-00-00 |
| RedBird  | Yin   | Bus     | m    | 1998-01-30 | NULL       |
+----------+-------+---------+------+------------+------------+
3 rows in set (0.00 sec)

mysql> SELECT * FROM Bird WHERE name LIKE 'B%';
+----------+-------+---------+------+------------+-------+
| name     | owner | species | sex  | birth      | death |
+----------+-------+---------+------+------------+-------+
| BlueBird | Joe   | Car     | f    | 1999-03-30 | NULL  |
+----------+-------+---------+------+------------+-------+
1 row in set (0.00 sec)


*/  
  
Drop table Bird;

CREATE TABLE Bird (
    name VARCHAR(20)
    owner VARCHAR(20),
    species VARCHAR(20)
    sex CHAR(1)
    birth DATE, 
    death DATE
);
  
INSERT INTO  Bird VALUES ('BlueBird','Joe','Car','f','1999-03-30',NULL);
INSERT INTO  Bird VALUES ('RedBird','Yin','Bus','m','1979-04-30',1998-01-30);
INSERT INTO  Bird VALUES ('RedBird','Yin','Bus','m','1998-01-30',NULL);
  
select from Bird;

SELECT FROM Bird WHERE name LIKE 'B%';

           
       
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