Source Code Cross Referenced for MergeState.java in  » Testing » Marathon » org » python » core » Java Source Code / Java DocumentationJava Source Code and Java Documentation

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Java Source Code / Java Documentation » Testing » Marathon » org.python.core 
Source Cross Referenced  Class Diagram Java Document (Java Doc) 


001:        // Copyright 2002 Finn Bock
002:
003:        package org.python.core;
004:
005:        /**
006:         * The MergeState class is a java implementation of the sort created
007:         * Tim Peters and added to CPython2.3.
008:         *
009:         * The algorithm is described in details in the file
010:         * python/dist/src/Objects/listsort.txt in the CPython development CVS.
011:         */
012:        class MergeState {
013:            /**
014:             * The maximum number of entries in a MergeState's pending-runs stack.
015:             * This is enough to sort arrays of size up to about
016:             *     32 * phi ** MAX_MERGE_PENDING
017:             * where phi ~= 1.618.  85 is ridiculously large enough, good for an
018:             * array with 2**64 elements.
019:             */
020:            static final int MAX_MERGE_PENDING = 85;
021:
022:            /**
023:             * If a run wins MIN_GALLOP times in a row, we switch to galloping mode,
024:             * and stay there until both runs win less often than MIN_GALLOP
025:             * consecutive times.  See listsort.txt for more info.
026:             */
027:            static final int MIN_GALLOP = 8;
028:
029:            /**
030:             * Initial temp array size
031:             */
032:            static final int MERGESTATE_TEMP_SIZE = 256;
033:
034:            private PyObject[] a = new PyObject[MERGESTATE_TEMP_SIZE];
035:
036:            private int[] base = new int[MAX_MERGE_PENDING];
037:            private int[] len = new int[MAX_MERGE_PENDING];
038:
039:            private PyObject compare;
040:            private PyObject[] data;
041:            private int size;
042:            private int n;
043:
044:            MergeState(PyObject[] data, int size, PyObject compare) {
045:                this .data = data;
046:                this .compare = compare;
047:                this .size = size;
048:                this .n = 0;
049:            }
050:
051:            public void sort() {
052:                int nremaining = this .size;
053:                if (nremaining < 2) {
054:                    return;
055:                }
056:
057:                int lo = 0;
058:                int hi = nremaining;
059:                int minrun = merge_compute_minrun(nremaining);
060:
061:                boolean[] descending = new boolean[1];
062:                do {
063:                    /* Identify next run. */
064:                    int localN = count_run(lo, hi, descending);
065:                    if (descending[0])
066:                        reverse_slice(lo, lo + localN);
067:                    /* If short, extend to min(minrun, nremaining). */
068:                    if (localN < minrun) {
069:                        int force = nremaining < minrun ? nremaining : minrun;
070:                        binarysort(lo, lo + force, lo + localN);
071:                        localN = force;
072:                    }
073:                    /* Push run onto pending-runs stack, and maybe merge. */
074:                    //ms.assert_(ms.n < ms.MAX_MERGE_PENDING);
075:                    this .base[this .n] = lo;
076:                    this .len[this .n] = localN;
077:                    ++this .n;
078:                    merge_collapse();
079:                    /* Advance to find next run */
080:                    lo += localN;
081:                    nremaining -= localN;
082:                } while (nremaining != 0);
083:                //assert_(lo == hi);
084:
085:                merge_force_collapse();
086:                //assert_(ms.n == 1);
087:                //assert_(ms.base[0] == 0);
088:                //assert_(ms.len[0] == size);
089:            }
090:
091:            public void getmem(int need) {
092:                if (need <= this .a.length)
093:                    return;
094:                this .a = new PyObject[need];
095:            }
096:
097:            int count_run(int lo, int hi, boolean[] descending) {
098:                //assert_(lo < hi);
099:                descending[0] = false;
100:                ++lo;
101:                if (lo == hi)
102:                    return 1;
103:                int localN = 2;
104:                if (iflt(this .data[lo], this .data[lo - 1])) {
105:                    descending[0] = true;
106:                    for (lo = lo + 1; lo < hi; ++lo, ++localN) {
107:                        if (!iflt(this .data[lo], this .data[lo - 1]))
108:                            break;
109:                    }
110:                } else {
111:                    for (lo = lo + 1; lo < hi; ++lo, ++localN) {
112:                        if (iflt(this .data[lo], this .data[lo - 1]))
113:                            break;
114:                    }
115:                }
116:                return localN;
117:            }
118:
119:            void merge_lo(int pa, int na, int pb, int nb) {
120:                //debug("merge_lo pa:" + pa + " na:" + na + " pb:" + pb + " nb:" + nb);
121:                //dump_data("padata", pa, na);
122:                //dump_data("pbdata", pb, nb);
123:
124:                //assert_(na > 0 && nb > 0 && pa + na == pb);
125:                getmem(na);
126:                System.arraycopy(this .data, pa, this .a, 0, na);
127:                int dest = pa;
128:                pa = 0;
129:
130:                this .data[dest++] = this .data[pb++];
131:                --nb;
132:                if (nb == 0)
133:                    return;
134:                if (na == 1) {
135:                    // CopyB;
136:                    System.arraycopy(this .data, pb, this .data, dest, nb);
137:                    this .data[dest + nb] = this .a[pa];
138:                    return;
139:                }
140:
141:                try {
142:                    for (;;) {
143:                        int acount = 0; /* # of time A won in a row */
144:                        int bcount = 0; /* # of time B won in a row */
145:
146:                        /* Do the straightforward thing until (if ever) one run
147:                         * appears to win consistently.
148:                         */
149:                        for (;;) {
150:                            boolean k = iflt(this .data[pb], this .a[pa]);
151:                            if (k) {
152:                                this .data[dest++] = this .data[pb++];
153:                                ++bcount;
154:                                acount = 0;
155:                                --nb;
156:                                if (nb == 0)
157:                                    return;
158:                                if (bcount >= MIN_GALLOP)
159:                                    break;
160:                            } else {
161:                                this .data[dest++] = this .a[pa++];
162:                                ++acount;
163:                                bcount = 0;
164:                                --na;
165:                                if (na == 1) {
166:                                    // CopyB;
167:                                    System.arraycopy(this .data, pb, this .data,
168:                                            dest, nb);
169:                                    this .data[dest + nb] = this .a[pa];
170:                                    na = 0;
171:                                    return;
172:                                }
173:                                if (acount >= MIN_GALLOP)
174:                                    break;
175:                            }
176:                        }
177:
178:                        /* One run is winning so consistently that galloping may
179:                         * be a huge win. So try that, and continue galloping until
180:                         * (if ever) neither run appears to be winning consistently
181:                         * anymore.
182:                         */
183:                        do {
184:                            int k = gallop_right(this .data[pb], this .a, pa, na,
185:                                    0);
186:                            acount = k;
187:                            if (k != 0) {
188:                                System
189:                                        .arraycopy(this .a, pa, this .data, dest,
190:                                                k);
191:                                dest += k;
192:                                pa += k;
193:                                na -= k;
194:                                if (na == 1) {
195:                                    // CopyB
196:                                    System.arraycopy(this .data, pb, this .data,
197:                                            dest, nb);
198:                                    this .data[dest + nb] = this .a[pa];
199:                                    na = 0;
200:                                    return;
201:                                }
202:                                /* na==0 is impossible now if the comparison
203:                                 * function is consistent, but we can't assume
204:                                 * that it is.
205:                                 */
206:                                if (na == 0)
207:                                    return;
208:                            }
209:
210:                            this .data[dest++] = this .data[pb++];
211:                            --nb;
212:                            if (nb == 0)
213:                                return;
214:
215:                            k = gallop_left(this .a[pa], this .data, pb, nb, 0);
216:                            bcount = k;
217:                            if (k != 0) {
218:                                System.arraycopy(this .data, pb, this .data,
219:                                        dest, k);
220:                                dest += k;
221:                                pb += k;
222:                                nb -= k;
223:                                if (nb == 0)
224:                                    return;
225:                            }
226:                            this .data[dest++] = this .a[pa++];
227:                            --na;
228:                            if (na == 1) {
229:                                // CopyB;
230:                                System.arraycopy(this .data, pb, this .data,
231:                                        dest, nb);
232:                                this .data[dest + nb] = this .a[pa];
233:                                na = 0;
234:                                return;
235:                            }
236:                        } while (acount >= MIN_GALLOP || bcount >= MIN_GALLOP);
237:                    }
238:                } finally {
239:                    if (na != 0)
240:                        System.arraycopy(this .a, pa, this .data, dest, na);
241:
242:                    //dump_data("result", origpa, cnt);
243:                }
244:            }
245:
246:            void merge_hi(int pa, int na, int pb, int nb) {
247:                //debug("merge_hi pa:" + pa + " na:" + na + " pb:" + pb + " nb:" + nb);
248:                //dump_data("padata", pa, na);
249:                //dump_data("pbdata", pb, nb);
250:
251:                //assert_(na > 0 && nb > 0 && pa + na == pb);
252:                getmem(nb);
253:                int dest = pb + nb - 1;
254:                int basea = pa;
255:                System.arraycopy(this .data, pb, this .a, 0, nb);
256:
257:                pb = nb - 1;
258:                pa += na - 1;
259:
260:                this .data[dest--] = this .data[pa--];
261:                --na;
262:                if (na == 0)
263:                    return;
264:                if (nb == 1) {
265:                    // CopyA;
266:                    dest -= na;
267:                    pa -= na;
268:                    System
269:                            .arraycopy(this .data, pa + 1, this .data, dest + 1,
270:                                    na);
271:                    this .data[dest] = this .a[pb];
272:                    nb = 0;
273:                    return;
274:                }
275:
276:                try {
277:                    for (;;) {
278:                        int acount = 0; /* # of time A won in a row */
279:                        int bcount = 0; /* # of time B won in a row */
280:
281:                        /* Do the straightforward thing until (if ever) one run
282:                         * appears to win consistently.
283:                         */
284:                        for (;;) {
285:                            boolean k = iflt(this .a[pb], this .data[pa]);
286:                            if (k) {
287:                                this .data[dest--] = this .data[pa--];
288:                                ++acount;
289:                                bcount = 0;
290:                                --na;
291:                                if (na == 0)
292:                                    return;
293:                                if (acount >= MIN_GALLOP)
294:                                    break;
295:                            } else {
296:                                this .data[dest--] = this .a[pb--];
297:                                ++bcount;
298:                                acount = 0;
299:                                --nb;
300:                                if (nb == 1) {
301:                                    // CopyA
302:                                    dest -= na;
303:                                    pa -= na;
304:                                    System.arraycopy(this .data, pa + 1,
305:                                            this .data, dest + 1, na);
306:                                    this .data[dest] = this .a[pb];
307:                                    nb = 0;
308:                                    return;
309:                                }
310:                                if (bcount >= MIN_GALLOP)
311:                                    break;
312:                            }
313:                        }
314:
315:                        /* One run is winning so consistently that galloping may
316:                         * be a huge win. So try that, and continue galloping until
317:                         * (if ever) neither run appears to be winning consistently
318:                         * anymore.
319:                         */
320:                        do {
321:                            int k = gallop_right(this .a[pb], this .data, basea,
322:                                    na, na - 1);
323:                            acount = k = na - k;
324:                            if (k != 0) {
325:                                dest -= k;
326:                                pa -= k;
327:                                System.arraycopy(this .data, pa + 1, this .data,
328:                                        dest + 1, k);
329:                                na -= k;
330:                                if (na == 0)
331:                                    return;
332:                            }
333:
334:                            this .data[dest--] = this .a[pb--];
335:                            --nb;
336:                            if (nb == 1) {
337:                                // CopyA
338:                                dest -= na;
339:                                pa -= na;
340:                                System.arraycopy(this .data, pa + 1, this .data,
341:                                        dest + 1, na);
342:                                this .data[dest] = this .a[pb];
343:                                nb = 0;
344:                                return;
345:                            }
346:
347:                            k = gallop_left(this .data[pa], this .a, 0, nb,
348:                                    nb - 1);
349:                            bcount = k = nb - k;
350:                            if (k != 0) {
351:                                dest -= k;
352:                                pb -= k;
353:                                System.arraycopy(this .a, pb + 1, this .data,
354:                                        dest + 1, k);
355:                                nb -= k;
356:                                if (nb == 1) {
357:                                    // CopyA
358:                                    dest -= na;
359:                                    pa -= na;
360:                                    System.arraycopy(this .data, pa + 1,
361:                                            this .data, dest + 1, na);
362:                                    this .data[dest] = this .a[pb];
363:                                    nb = 0;
364:                                    return;
365:                                }
366:                                /* nb==0 is impossible now if the comparison
367:                                 * function is consistent, but we can't assume
368:                                 * that it is.
369:                                 */
370:                                if (nb == 0)
371:                                    return;
372:                            }
373:                            this .data[dest--] = this .data[pa--];
374:                            --na;
375:                            if (na == 0)
376:                                return;
377:                        } while (acount >= MIN_GALLOP || bcount >= MIN_GALLOP);
378:                    }
379:                } finally {
380:                    if (nb != 0)
381:                        System.arraycopy(this .a, 0, this .data, dest - (nb - 1),
382:                                nb);
383:
384:                    //dump_data("result", origpa, cnt);
385:                }
386:            }
387:
388:            /*
389:             Locate the proper position of key in a sorted vector; if the vector contains
390:             an element equal to key, return the position immediately to the left of
391:             the leftmost equal element.  [gallop_right() does the same except returns
392:             the position to the right of the rightmost equal element (if any).]
393:             
394:             "a" is a sorted vector with n elements, starting at a[0].  n must be > 0.
395:             
396:             "hint" is an index at which to begin the search, 0 <= hint < n.  The closer
397:             hint is to the final result, the faster this runs.
398:             
399:             The return value is the int k in 0..n such that
400:             
401:                 a[k-1] < key <= a[k]
402:             
403:             pretending that *(a-1) is minus infinity and a[n] is plus infinity.  IOW,
404:             key belongs at index k; or, IOW, the first k elements of a should precede
405:             key, and the last n-k should follow key.
406:
407:             Returns -1 on error.  See listsort.txt for info on the method.
408:             */
409:
410:            private int gallop_left(PyObject key, PyObject[] localData,
411:                    int localA, int localN, int hint) {
412:                //assert_(n > 0 && hint >= 0 && hint < n);
413:                localA += hint;
414:                int ofs = 1;
415:                int lastofs = 0;
416:
417:                if (iflt(localData[localA], key)) {
418:                    /* a[hint] < key -- gallop right, until
419:                     * a[hint + lastofs] < key <= a[hint + ofs]
420:                     */
421:                    int maxofs = localN - hint; // data[a + n - 1] is highest
422:                    while (ofs < maxofs) {
423:                        if (iflt(localData[localA + ofs], key)) {
424:                            lastofs = ofs;
425:                            ofs = (ofs << 1) + 1;
426:                            if (ofs <= 0) // int overflow
427:                                ofs = maxofs;
428:                        } else {
429:                            // key < data[a + hint + ofs]
430:                            break;
431:                        }
432:                    }
433:                    if (ofs > maxofs)
434:                        ofs = maxofs;
435:                    // Translate back to offsets relative to a.
436:                    lastofs += hint;
437:                    ofs += hint;
438:                } else {
439:                    /* key <= a[hint] -- gallop left, until
440:                     * a[hint - ofs] < key <= a[hint - lastofs]
441:                     */
442:                    int maxofs = hint + 1; // data[a] is lowest
443:                    while (ofs < maxofs) {
444:                        if (iflt(localData[localA - ofs], key))
445:                            break;
446:                        // key <= data[a + hint - ofs]
447:                        lastofs = ofs;
448:                        ofs = (ofs << 1) + 1;
449:                        if (ofs <= 0) // int overflow
450:                            ofs = maxofs;
451:                    }
452:                    if (ofs > maxofs)
453:                        ofs = maxofs;
454:                    // Translate back to offsets relative to a.
455:                    int k = lastofs;
456:                    lastofs = hint - ofs;
457:                    ofs = hint - k;
458:                }
459:                localA -= hint;
460:                //assert_(-1 <= lastofs && lastofs < ofs && ofs <= n);
461:                /* Now a[lastofs] < key <= a[ofs], so key belongs somewhere to the
462:                 * right of lastofs but no farther right than ofs.  Do a binary
463:                 * search, with invariant a[lastofs-1] < key <= a[ofs].
464:                 */
465:                ++lastofs;
466:                while (lastofs < ofs) {
467:                    int m = lastofs + ((ofs - lastofs) >> 1);
468:                    if (iflt(localData[localA + m], key))
469:                        lastofs = m + 1; // data[a + m] < key
470:                    else
471:                        ofs = m; // key <= data[a + m]
472:                }
473:                //assert_(lastofs == ofs); // so data[a + ofs -1] < key <= data[a+ofs]
474:                return ofs;
475:            }
476:
477:            /*
478:             * Exactly like gallop_left(), except that if key already exists in a[0:n],
479:             * finds the position immediately to the right of the rightmost equal value.
480:             *  
481:             * The return value is the int k in 0..n such that
482:             *     a[k-1] <= key < a[k]
483:             * or -1 if error.
484:             *  
485:             * The code duplication is massive, but this is enough different given that
486:             * we're sticking to "<" comparisons that it's much harder to follow if
487:             * written as one routine with yet another "left or right?" flag.
488:             */
489:
490:            private int gallop_right(PyObject key, PyObject[] aData,
491:                    int localA, int localN, int hint) {
492:                //assert_(n > 0 && hint >= 0 && hint < n);
493:                localA += hint;
494:                int lastofs = 0;
495:                int ofs = 1;
496:
497:                if (iflt(key, aData[localA])) {
498:                    /* key < a[hint] -- gallop left, until
499:                     * a[hint - ofs] <= key < a[hint - lastofs]
500:                     */
501:                    int maxofs = hint + 1; /* data[a] is lowest */
502:                    while (ofs < maxofs) {
503:                        if (iflt(key, aData[localA - ofs])) {
504:                            lastofs = ofs;
505:                            ofs = (ofs << 1) + 1;
506:                            if (ofs <= 0) // int overflow
507:                                ofs = maxofs;
508:                        } else {
509:                            /* a[hint - ofs] <= key */
510:                            break;
511:                        }
512:                    }
513:                    if (ofs > maxofs)
514:                        ofs = maxofs;
515:                    /* Translate back to positive offsets relative to &a[0]. */
516:                    int k = lastofs;
517:                    lastofs = hint - ofs;
518:                    ofs = hint - k;
519:                } else {
520:                    /* a[hint] <= key -- gallop right, until
521:                     * a[hint + lastofs] <= key < a[hint + ofs]
522:                     */
523:                    int maxofs = localN - hint; /* data[a + n - 1] is highest */
524:                    while (ofs < maxofs) {
525:                        if (iflt(key, aData[localA + ofs]))
526:                            break;
527:                        /* a[hint + ofs] <= key */
528:                        lastofs = ofs;
529:                        ofs = (ofs << 1) + 1;
530:                        if (ofs <= 0) /* int overflow */
531:                            ofs = maxofs;
532:                    }
533:                    if (ofs > maxofs)
534:                        ofs = maxofs;
535:                    /* Translate back to offsets relative to &a[0]. */
536:                    lastofs += hint;
537:                    ofs += hint;
538:                }
539:                localA -= hint;
540:
541:                //assert_(-1 <= lastofs && lastofs < ofs && ofs <= n);
542:
543:                /* Now a[lastofs] <= key < a[ofs], so key belongs somewhere to the
544:                 * right of lastofs but no farther right than ofs.  Do a binary
545:                 * search, with invariant a[lastofs-1] <= key < a[ofs].
546:                 */
547:                ++lastofs;
548:                while (lastofs < ofs) {
549:                    int m = lastofs + ((ofs - lastofs) >> 1);
550:                    if (iflt(key, aData[localA + m]))
551:                        ofs = m; // key < data[a + m]
552:                    else
553:                        lastofs = m + 1; // data[a + m] <= key
554:                }
555:                //assert_(lastofs == ofs); // so data[a + ofs -1] <= key < data[a+ofs]
556:                return ofs;
557:            }
558:
559:            void merge_at(int i) {
560:                //assert_(n >= 2);
561:                //assert_(i >= 0);
562:                //assert_(i == n - 2 || i == n - 3);
563:
564:                int pa = this .base[i];
565:                int pb = this .base[i + 1];
566:                int na = this .len[i];
567:                int nb = this .len[i + 1];
568:
569:                //assert_(na > 0 && nb > 0);
570:                //assert_(pa + na == pb);
571:
572:                // Record the length of the combined runs; if i is the 3rd-last
573:                // run now, also slide over the last run (which isn't involved
574:                // in this merge).  The current run i+1 goes away in any case.
575:                if (i == this .n - 3) {
576:                    this .len[i + 1] = this .len[i + 2];
577:                    this .base[i + 1] = this .base[i + 2];
578:                }
579:                this .len[i] = na + nb;
580:                --this .n;
581:
582:                // Where does b start in a?  Elements in a before that can be
583:                // ignored (already in place).
584:                int k = gallop_right(this .data[pb], this .data, pa, na, 0);
585:                pa += k;
586:                na -= k;
587:                if (na == 0)
588:                    return;
589:
590:                // Where does a end in b?  Elements in b after that can be
591:                // ignored (already in place).
592:                nb = gallop_left(this .data[pa + na - 1], this .data, pb, nb,
593:                        nb - 1);
594:                if (nb == 0)
595:                    return;
596:
597:                // Merge what remains of the runs, using a temp array with
598:                // min(na, nb) elements.
599:                if (na <= nb)
600:                    merge_lo(pa, na, pb, nb);
601:                else
602:                    merge_hi(pa, na, pb, nb);
603:            }
604:
605:            /* Examine the stack of runs waiting to be merged, merging adjacent runs
606:             * until the stack invariants are re-established:
607:             *
608:             * 1. len[-3] > len[-2] + len[-1]
609:             * 2. len[-2] > len[-1]
610:             *
611:             * See listsort.txt for more info.
612:             */
613:            void merge_collapse() {
614:                while (this .n > 1) {
615:                    int localN = this .n - 2;
616:                    if (localN > 0
617:                            && this .len[localN - 1] <= this .len[localN]
618:                                    + this .len[localN + 1]) {
619:                        if (this .len[localN - 1] < this .len[localN + 1])
620:                            --localN;
621:                        merge_at(localN);
622:                    } else if (this .len[localN] <= this .len[localN + 1]) {
623:                        merge_at(localN);
624:                    } else {
625:                        break;
626:                    }
627:                }
628:            }
629:
630:            /* Regardless of invariants, merge all runs on the stack until only one
631:             * remains.  This is used at the end of the mergesort.
632:             *
633:             * Returns 0 on success, -1 on error.
634:             */
635:            void merge_force_collapse() {
636:                while (this .n > 1) {
637:                    int localN = this .n - 2;
638:                    if (localN > 0
639:                            && this .len[localN - 1] < this .len[localN + 1])
640:                        --localN;
641:                    merge_at(localN);
642:                }
643:            }
644:
645:            /* Compute a good value for the minimum run length; natural runs shorter
646:             * than this are boosted artificially via binary insertion.
647:             *
648:             * If n < 64, return n (it's too small to bother with fancy stuff).
649:             * Else if n is an exact power of 2, return 32.
650:             * Else return an int k, 32 <= k <= 64, such that n/k is close to, but
651:             * strictly less than, an exact power of 2.
652:             *
653:             * See listsort.txt for more info.
654:             */
655:            int merge_compute_minrun(int localN) {
656:                int r = 0; // becomes 1 if any 1 bits are shifted off
657:
658:                //assert_(n >= 0);
659:                while (localN >= 64) {
660:                    r |= localN & 1;
661:                    localN >>= 1;
662:                }
663:                return localN + r;
664:            }
665:
666:            void assert_(boolean expr) {
667:                if (!expr)
668:                    throw new RuntimeException("assert");
669:            }
670:
671:            private boolean iflt(PyObject x, PyObject y) {
672:                //assert_(x != null);
673:                //assert_(y != null);
674:
675:                if (this .compare == null) {
676:                    /* NOTE: we rely on the fact here that the sorting algorithm
677:                       only ever checks whether k<0, i.e., whether x<y.  So we
678:                       invoke the rich comparison function with _lt ('<'), and
679:                       return -1 when it returns true and 0 when it returns
680:                       false. */
681:                    return x._lt(y).__nonzero__();
682:                }
683:
684:                PyObject ret = this .compare.__call__(x, y);
685:
686:                if (ret instanceof  PyInteger) {
687:                    int v = ((PyInteger) ret).getValue();
688:                    return v < 0;
689:                }
690:                throw Py.TypeError("comparision function must return int");
691:            }
692:
693:            void reverse_slice(int lo, int hi) {
694:                --hi;
695:                while (lo < hi) {
696:                    PyObject t = this .data[lo];
697:                    this .data[lo] = this .data[hi];
698:                    this .data[hi] = t;
699:                    ++lo;
700:                    --hi;
701:                }
702:            }
703:
704:            /*
705:             * binarysort is the best method for sorting small arrays: it does
706:             * few compares, but can do data movement quadratic in the number of
707:             * elements.
708:             * [lo, hi) is a contiguous slice of a list, and is sorted via
709:             * binary insertion.  This sort is stable.
710:             * On entry, must have lo <= start <= hi, and that [lo, start) is already
711:             * sorted (pass start == lo if you don't know!).
712:             * If islt() complains return -1, else 0.
713:             * Even in case of error, the output slice will be some permutation of
714:             * the input (nothing is lost or duplicated).
715:             */
716:            void binarysort(int lo, int hi, int start) {
717:                //debug("binarysort: lo:" + lo + " hi:" + hi + " start:" + start);
718:                int p;
719:
720:                //assert_(lo <= start && start <= hi);
721:                /* assert [lo, start) is sorted */
722:                if (lo == start)
723:                    ++start;
724:                for (; start < hi; ++start) {
725:                    /* set l to where *start belongs */
726:                    int l = lo;
727:                    int r = start;
728:                    PyObject pivot = this .data[r];
729:                    // Invariants:
730:                    // pivot >= all in [lo, l).
731:                    // pivot  < all in [r, start).
732:                    // The second is vacuously true at the start.
733:                    //assert_(l < r);
734:                    do {
735:                        p = l + ((r - l) >> 1);
736:                        if (iflt(pivot, this .data[p]))
737:                            r = p;
738:                        else
739:                            l = p + 1;
740:                    } while (l < r);
741:                    //assert_(l == r);
742:                    // The invariants still hold, so pivot >= all in [lo, l) and
743:                    // pivot < all in [l, start), so pivot belongs at l.  Note
744:                    // that if there are elements equal to pivot, l points to the
745:                    // first slot after them -- that's why this sort is stable.
746:                    // Slide over to make room.
747:                    for (p = start; p > l; --p)
748:                        this .data[p] = this .data[p - 1];
749:                    this .data[l] = pivot;
750:                }
751:                //dump_data("binsort", lo, hi - lo);
752:            }
753:
754:            /*  //debugging methods.
755:             private void dump_data(String txt, int lo, int n) {
756:             System.out.print(txt + ":");
757:             for (int i = 0; i < n; i++)
758:             System.out.print(data[lo + i] + " ");
759:             System.out.println();
760:             }
761:             private void debug(String str) {
762:             //System.out.println(str);
763:             }
764:             */
765:        }
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