Returns the position of the second occurrence that matches the letter o starting at position 10 using REGEXP_INSTR() : REGEXP_INSTR « Regular Expressions Functions « Oracle PL/SQL Tutorial

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Oracle PL/SQL Tutorial » Regular Expressions Functions » REGEXP_INSTR

18. 2. 12. Returns the position of the second occurrence that matches the letter o starting at position 10 using REGEXP_INSTR()


SQL>

SQL> SELECT REGEXP_INSTR('abcedfghijklumnoprstuvwxyzabcedfghijklumnoprstuvwxyzabcedfghijklumnoprstuvwxyz', 'o', 10, 2) AS result

  2  FROM dual;



    RESULT

----------

        42



SQL>

18. 2. REGEXP_INSTR
	18. 2. 1.	Regexp_Instr returns the location (beginning) of a pattern in a given string
	18. 2. 2.	REGEXP_INSTR(x, pattern [, start [, occurrence [, return_option [, match_option]]]]) searches for pattern in x.
	18. 2. 3.	Regexp_Instr
	18. 2. 4.	Parameters is a field that may be used to define how one wants the search to proceed:
	18. 2. 5.	Find the 's' and ignore case.
	18. 2. 6.	The simplest regular expression matches letters, letter for letter
	18. 2. 7.	SELECT REGEXP_INSTR('Two is bigger than One','One') where_it_is
	18. 2. 8.	Occurrence refers to the first, second, third, etc., occurrence of the pattern in S. The default is 1 (first).
	18. 2. 9.	Return-option returns the position of the start or end of the matched string.
	18. 2. 10.	The Return-option is set to 1 to indicate the end of the found pattern
	18. 2. 11.	Returns the position of the second occurrence that matches the regular expression s[[:alpha:]]{3} starting at position 1:
	18. 2. 12.	Returns the position of the second occurrence that matches the letter o starting at position 10 using REGEXP_INSTR()
	18. 2. 13.	Specify any series of letters and find matches, just like INSTR
	18. 2. 14.	regexp_instr(comments, '[^ ]+', 1, 9) > 0

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