Getting Information on the Indexes on a Column : user_ind_columns « System Tables Data Dictionary « Oracle PL/SQL Tutorial

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Oracle PL/SQL Tutorial » System Tables Data Dictionary » user_ind_columns 
30. 81. 1. Getting Information on the Indexes on a Column

You can get information on the indexes on a column by querying user_ind_columns.

SQL> desc user_ind_columns;
 Name                    Null?    Type
 ------------------------

 INDEX_NAME                       VARCHAR2(30)
 TABLE_NAME                       VARCHAR2(30)
 COLUMN_NAME                      VARCHAR2(4000)
 COLUMN_POSITION                  NUMBER
 COLUMN_LENGTH                    NUMBER
 CHAR_LENGTH                      NUMBER
 DESCEND                          VARCHAR2(4)
SQL>
SQL>
SQL> -- create demo table
SQL> create table Employee(
  2    ID                 VARCHAR2(BYTE)         NOT NULL,
  3    First_Name         VARCHAR2(10 BYTE),
  4    Last_Name          VARCHAR2(10 BYTE),
  5    Start_Date         DATE,
  6    End_Date           DATE,
  7    Salary             Number(8,2),
  8    City               VARCHAR2(10 BYTE),
  9    Description        VARCHAR2(15 BYTE)
 10  )
 11  /

Table created.

SQL>
SQL> -- prepare data
SQL> insert into Employee(ID,  First_Name, Last_Name, Start_Date,                     End_Date,                       Salary,  City,       Description)
  2               values ('01','Jason',    'Martin',  to_date('19960725','YYYYMMDD'), to_date('20060725','YYYYMMDD'), 1234.56'Toronto',  'Programmer')
  3  /

row created.

SQL> insert into Employee(ID,  First_Name, Last_Name, Start_Date,                     End_Date,                       Salary,  City,       Description)
  2                values('02','Alison',   'Mathews', to_date('19760321','YYYYMMDD'), to_date('19860221','YYYYMMDD'), 6661.78'Vancouver','Tester')
  3  /

row created.

SQL> insert into Employee(ID,  First_Name, Last_Name, Start_Date,                     End_Date,                       Salary,  City,       Description)
  2                values('03','James',    'Smith',   to_date('19781212','YYYYMMDD'), to_date('19900315','YYYYMMDD'), 6544.78'Vancouver','Tester')
  3  /

row created.

SQL> insert into Employee(ID,  First_Name, Last_Name, Start_Date,                     End_Date,                       Salary,  City,       Description)
  2                values('04','Celia',    'Rice',    to_date('19821024','YYYYMMDD'), to_date('19990421','YYYYMMDD'), 2344.78'Vancouver','Manager')
  3  /

row created.

SQL> insert into Employee(ID,  First_Name, Last_Name, Start_Date,                     End_Date,                       Salary,  City,       Description)
  2                values('05','Robert',   'Black',   to_date('19840115','YYYYMMDD'), to_date('19980808','YYYYMMDD'), 2334.78'Vancouver','Tester')
  3  /

row created.

SQL> insert into Employee(ID,  First_Name, Last_Name, Start_Date,                     End_Date,                       Salary, City,        Description)
  2                values('06','Linda',    'Green',   to_date('19870730','YYYYMMDD'), to_date('19960104','YYYYMMDD'), 4322.78,'New York',  'Tester')
  3  /

row created.

SQL> insert into Employee(ID,  First_Name, Last_Name, Start_Date,                     End_Date,                       Salary, City,        Description)
  2                values('07','David',    'Larry',   to_date('19901231','YYYYMMDD'), to_date('19980212','YYYYMMDD'), 7897.78,'New York',  'Manager')
  3  /

row created.

SQL> insert into Employee(ID,  First_Name, Last_Name, Start_Date,                     End_Date,                       Salary, City,        Description)
  2                values('08','James',    'Cat',     to_date('19960917','YYYYMMDD'), to_date('20020415','YYYYMMDD'), 1232.78,'Vancouver', 'Tester')
  3  /

row created.

SQL>
SQL>
SQL>
SQL> -- display data in the table
SQL> select from Employee
  2  /

ID   FIRST_NAME LAST_NAME  START_DAT END_DATE      SALARY CITY       DESCRIPTION
---- ---------- ---------- --------- --------- ---------- ---------- ---------------
01   Jason      Martin     25-JUL-96 25-JUL-06    1234.56 Toronto    Programmer
02   Alison     Mathews    21-MAR-76 21-FEB-86    6661.78 Vancouver  Tester
03   James      Smith      12-DEC-78 15-MAR-90    6544.78 Vancouver  Tester
04   Celia      Rice       24-OCT-82 21-APR-99    2344.78 Vancouver  Manager
05   Robert     Black      15-JAN-84 08-AUG-98    2334.78 Vancouver  Tester
06   Linda      Green      30-JUL-87 04-JAN-96    4322.78 New York   Tester
07   David      Larry      31-DEC-90 12-FEB-98    7897.78 New York   Manager
08   James      Cat        17-SEP-96 15-APR-02    1232.78 Vancouver  Tester

rows selected.

SQL>
SQL>
SQL> CREATE INDEX employee_last_name_func_idx
  2  ON employee(UPPER(last_name));

Index created.

SQL> SELECT first_name, last_name
  2  FROM employee
  3  WHERE last_name = UPPER('PRICE');

no rows selected

SQL>
SQL>
SQL> COLUMN table_name FORMAT a15
SQL> COLUMN column_name FORMAT a15
SQL> SELECT index_name, table_name, column_name
  2  FROM user_ind_columns
  3  WHERE table_name IN ('EMPLOYEE');

INDEX_NAME                     TABLE_NAME      COLUMN_NAME
------------------------------ --------------- ---------------
EMPLOYEE_LAST_NAME_FUNC_IDX    EMPLOYEE        SYS_NC00009$

SQL>
SQL> clear columns;
columns cleared
SQL>
SQL> drop index employee_last_name_func_idx;

Index dropped.

SQL> -- clean the table
SQL> drop table Employee
  2  /

Table dropped.

SQL>
SQL>
SQL>
SQL>
30. 81. user_ind_columns
30. 81. 1. Getting Information on the Indexes on a Column
30. 81. 2. Query table_name,index_name, index.uniqueness,index.status by joining user_indexes and user_ind_columns
30. 81. 3. Output report for user_ind_columns
30. 81. 4. user_indexes join user_ind_columns ic using (table_name,index_name)
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