Start process by setting file name : Process « Development « VB.Net Tutorial

1.	Language Basics
2.	Data Type
3.	Operator
4.	Statements
5.	Date Time
6.	Class Module
7.	Development
8.	Collections
9.	Generics
10.	Attributes
11.	Event
12.	LINQ
13.	Stream File
14.	GUI
15.	GUI Applications
16.	Windows Presentation Foundation
17.	2D Graphics
18.	I18N Internationlization
19.	Reflection
20.	Regular Expressions
21.	Security
22.	Socket Network
23.	Thread
24.	Windows
25.	XML
26.	Database ADO.net
27.	Design Patterns

VB.Net

VB.Net by API

VB.Net Tutorial » Development » Process

7.24.1.Start process by setting file name

Public Class Tester

    Public Shared Sub Main

    

        Dim proc As System.Diagnostics.Process

        proc = New System.Diagnostics.Process()

        proc.StartInfo.FileName = "c:\\text.txt"

        proc.Start()

    End Sub



End Class

Unhandled Exception: System.ComponentModel.Win32Exception: The system cannot find the file specified

   at System.Diagnostics.Process.StartWithShellExecuteEx(ProcessStartInfo startInfo)
   at System.Diagnostics.Process.Start()
   at Tester.Main()

7.24.Process
	7.24.1.	Start process by setting file name
	7.24.2.	Get current Process
	7.24.3.	Display properties of current Process
	7.24.4.	Start main module in current process
	7.24.5.	Kill current process
	7.24.6.	Get thread count in current process
	7.24.7.	Get Process by ID
	7.24.8.	Print properties of Process
	7.24.9.	Open Default editor for text file
	7.24.10.	Start a process
	7.24.11.	List all process in a ListView

www.java2java.com | Contact Us

All other trademarks are property of their respective owners.