Use Color.FromArgb to create Color : Color « 2D Graphics « C# / C Sharp

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C# / C Sharp » 2D Graphics » Color Screenshots  Use Color.FromArgb to create Color    using System; using System.Drawing; using System.Windows.Forms;     class RandomClear: Form  {      public static void Main()      {           Application.Run(new RandomClear());      }      public RandomClear()            {           Text = "Random Clear";      }      protected override void OnPaint(PaintEventArgs pea)      {           Graphics graphics = pea.Graphics;           Random   rand = new Random();               graphics.Clear(Color.FromArgb(rand.Next(256),                                     rand.Next(256),                                     rand.Next(256)));      } }        Related examples in the same category 1. Transparent color 2. List all known color in a system 3. Draw each of 100 cells with randomly chosen colors 4. Filled with the semi transparent and transparent color 5. All the colors that are supported in C# according 6. Color Changer 7. Known Colors 8. Five yellow squares with different alpha values(Transparensy) 9. Create two color instances with different alpha components 10. Color.Chocolate 11. Get all known color 12. Color representation in r,g,b with values [0.0 - 1.0]. 13. Color representation in h,s,v with h = [0 - 360], s,v = [0.0 - 1.0]. 14. Return a randomly-generated color