Explicitly implement an interface member : Interface « Class Interface « C# / C Sharp

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Explicitly implement an interface member
Explicitly implement an interface member

/*
C#: The Complete Reference 
by Herbert Schildt 

Publisher: Osborne/McGraw-Hill (March 8, 2002)
ISBN: 0072134852
*/


// Explicitly implement an interface member. 
 
using System; 
 
interface IEven 
  bool isOdd(int x)
  bool isEven(int x)

 
class MyClass : IEven 
  // explicit implementation 
  bool IEven.isOdd(int x) { 
    if((x%2!= 0return true
    else return false
  
 
  // normal implementation 
  public bool isEven(int x) { 
    IEven o = this// reference to invoking object 
 
    return !o.isOdd(x)
  

 
public class Demo 
  public static void Main() { 
    MyClass ob = new MyClass()
    bool result; 
 
    result = ob.isEven(4)
    if(resultConsole.WriteLine("4 is even.")
    else Console.WriteLine("3 is odd.")
 
    // result = ob.isOdd(); // Error, not exposed 
  
}

           
       
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