Overriding a template function. : Function Template « Function « C++

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C++ » Function » Function TemplateScreenshots 
Overriding a template function.
   
#include <iostream>
using namespace std;
   
template <class X> void swapargs(X &a, X &b)
{
  X temp;
   
  temp = a;
  a = b;
  b = temp;
  cout << "Inside template swapargs.\n";
}
   
// This overrides the generic version of swapargs() for ints.
void swapargs(int &a, int &b)
{
  int temp;
   
  temp = a;
  a = b;
  b = temp;
  cout << "Inside swapargs int specialization.\n";
}
   
int main()
{
  int i=10, j=20;
  double x=10.1, y=23.3;
  char a='x', b='z';
   
  cout << "Original i, j: " << i << ' ' << j << '\n';
  cout << "Original x, y: " << x << ' ' << y << '\n';
  cout << "Original a, b: " << a << ' ' << b << '\n';
   
  swapargs(i, j)// calls explicitly overloaded swapargs()
  swapargs(x, y)// calls generic swapargs()
  swapargs(a, b)// calls generic swapargs()
   
  cout << "Swapped i, j: " << i << ' ' << j << '\n';
  cout << "Swapped x, y: " << x << ' ' << y << '\n';
  cout << "Swapped a, b: " << a << ' ' << b << '\n';
   
  return 0;
}
  
    
    
  
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