count(distinct state) : COUNT « Aggregate Functions « Oracle PL / SQL

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Oracle PL / SQL » Aggregate Functions » COUNT 
count(distinct state)
  

SQL>
SQL> create table emp(
  2           emp_id                integer         primary key
  3          ,lastname               varchar2(20)    not null
  4          ,firstname              varchar2(15)    not null
  5          ,midinit                varchar2(1)
  6          ,street                 varchar2(30)
  7          ,city                   varchar2(20)
  8          ,state                  varchar2(2)
  9          ,zip                    varchar2(5)
 10          ,shortZipCode                   varchar2(4)
 11          ,area_code              varchar2(3)
 12          ,phone                  varchar2(8)
 13          ,company_name           varchar2(50));

Table created.

SQL>
SQL>
SQL> insert into emp(emp_id,lastname,firstname,midinit,street,city,state,zip,shortZipCode,area_code,phone,company_name)values
  2                      (1,'Jones','Joe','J','Ave','New York','NY','11202','1111','212', '221-4333','Big Company');

row created.

SQL> insert into emp(emp_id,lastname,firstname,midinit,street,city,state,zip,shortZipCode,area_code,phone,company_name)values
  2                      (2,'Smith','Sue','J','Street','New York','NY','11444','1111','212', '436-6773','Little Company');

row created.

SQL> insert into emp(emp_id,lastname,firstname,midinit,street,city,state,zip,shortZipCode,area_code,phone,company_name)values
  2                      (3,'X','Peggy','J','Drive','New York','NY','45502','2222','212', '234-4444','Medium Company');

row created.

SQL> insert into emp(emp_id,lastname,firstname,midinit,street,city,state,zip,shortZipCode,area_code,phone,company_name)values
  2                      (4,'Murdy','Jill', null,'93Eady St','New York','NY','45452','6458','212', '634-7733','Wilton Company');

row created.

SQL> insert into emp(emp_id,lastname,firstname,midinit,street,city,state,zip,shortZipCode,area_code,phone,company_name)values
  2                      (5,'Oper','Carl','L','19 Studio Drive','New York','NY','67672','3234','212', '243-4243','Wesson and Smith Company');

row created.

SQL>
SQL> select count(distinct statefrom emp;

COUNT(DISTINCTSTATE)
--------------------
                   1

row selected.

SQL> drop table emp;

Table dropped.

   
    
  
Related examples in the same category
1. COUNT(column) and COUNT(*): count the number of rows passed into the function.
2. Syntax: COUNT([DISTINCT]|[ALL] )
3. Using GROUP BY would tell us how many cars from each vendor we have on the lot:
4. Find out which maker has a null value car with count()
5. -Using the COUNT function in Having clause
6. Example using the COUNT function with group by clause
7. Count with group by: count for a group value
8. Get the number of rows in each city group using the COUNT() function
9. count null
10. Column alias name for count function
11. Count(*) - count(column_Name)
12. count distinct column value
13. count(1)
14. Count(*) and column renaming
15. Count() with where clause
16. Count date field value, and calculation
17. Count department and calculate average salary
18. Count employee in a department after grouping by department id
19. Count employee, group by department id and job title
20. count(*) - count(onhand)
21. count(*) vs count(column name)
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