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SQL> create table TestTable(
2 ID VARCHAR2(4 BYTE) NOT NULL,
3 Description VARCHAR2(30 BYTE)
4 )
5 /
Table created.
SQL>
SQL>
SQL> insert into TestTable (ID, Description) values('1','1234 5th Street');
1 row created.
SQL> insert into TestTable (ID, Description) values('2','1 Culloden Street');
1 row created.
SQL> insert into TestTable (ID, Description) values('3','1234 Road');
1 row created.
SQL> insert into TestTable (ID, Description) values('4','33 Thrid Road');
1 row created.
SQL> insert into TestTable (ID, Description) values('5','One than another');
1 row created.
SQL> insert into TestTable (ID, Description) values('6','2003 Movie');
1 row created.
SQL> insert into TestTable (ID, Description) values('7','Start With Letters');
1 row created.
SQL>
SQL> select * from TestTable;
ID DESCRIPTION
---- ------------------------------
1 1234 5th Street
2 1 Culloden Street
3 1234 Road
4 33 Thrid Road
5 One than another
6 2003 Movie
7 Start With Letters
7 rows selected.
SQL>
SQL> --Group the letters 'ir' together by putting them in parentheses and then parenthesizing the suffix using alternation:
SQL>
SQL> SELECT description, REGEXP_SUBSTR(description,'(ir)(d|s)') FROM testTable;
DESCRIPTION REGEXP_SUBSTR(DESCRIPTION,'(IR
------------------------------ ------------------------------
1234 5th Street
1 Culloden Street
1234 Road
33 Thrid Road
One than another
2003 Movie
Start With Letters
7 rows selected.
SQL>
SQL>
SQL>
SQL> drop table TestTable;
Table dropped.
SQL>
SQL>
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