|
SQL> create table TestTable(
2 ID VARCHAR2(4 BYTE) NOT NULL,
3 Description VARCHAR2(30 BYTE)
4 )
5 /
Table created.
SQL>
SQL>
SQL> insert into TestTable (ID, Description) values('1','1234 5th Street');
1 row created.
SQL> insert into TestTable (ID, Description) values('2','1 Culloden Street');
1 row created.
SQL> insert into TestTable (ID, Description) values('3','1234 Road');
1 row created.
SQL> insert into TestTable (ID, Description) values('4','33 Thrid Road');
1 row created.
SQL> insert into TestTable (ID, Description) values('5','One than another');
1 row created.
SQL> insert into TestTable (ID, Description) values('6','2003 Movie');
1 row created.
SQL> insert into TestTable (ID, Description) values('7','aeiou With Letters');
1 row created.
SQL>
SQL> select * from TestTable;
ID DESCRIPTION
---- ------------------------------
1 1234 5th Street
2 1 Culloden Street
3 1234 Road
4 33 Thrid Road
5 One than another
6 2003 Movie
7 aeiou With Letters
7 rows selected.
SQL>
SQL>
SQL> -- REGEXP_INSTR(description,'[aeiou]{3,5}'): Specify from three to five consecutive vowels, we'd get this:
SQL>
SQL> SELECT description,
2 REGEXP_INSTR(description,'[aeiou]{2,3}') where_pattern_starts
3 FROM testTable
4 WHERE REGEXP_INSTR(description,'[aeiou]{3,5}') > 0;
DESCRIPTION WHERE_PATTERN_STARTS
------------------------------ --------------------
aeiou With Letters 1
SQL>
SQL>
SQL>
SQL>
SQL> drop table TestTable;
Table dropped.
SQL>
SQL>
|