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DATEADD(year, 18, '4-29-1988 10:30 AM'): 18 years later |
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1>
2> -- 18 years later:
3>
4> SELECT DATEADD(year, 18, '4-29-1988 10:30 AM')
5> GO
-----------------------
2006-04-29 10:30:00.000
(1 rows affected)
1>
2>
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Related examples in the same category |
1. | DATEADD: add or subtract a number of days, months, or years from a specific date | | | 2. | SELECT DATEADD(yy,12,"24 March 1964"): Add 12 years to 24th March 1964 | | | 3. | SELECT DATEADD(m,12,"24 March 1964"): Add 12 months to 24th March 1964 | | | 4. | SELECT DATEADD(wk,12,"24 March 1964"): Add 12 weeks to 24th March 1964 | | | 5. | SELECT DATEADD(hh,12,"24 March 1964"): Add 12 hours to 24th March 1964 | | | 6. | Add 12 minutes to 24th March 1964 | | | 7. | DATEADD(Day, 90, '4-29-1988'): adds a specific number of date unit intervals to a date/time value | | | 8. | DATEADD(yy, -18, '4-29-1988 10:30 AM'): 18 years before | | | 9. | DATEADD(second, 9000, '4-29-1988 10:30 AM'): 9,000 seconds after | | | 10. | DATEADD(mi, -9000000, '4-29-1988 10:30 AM'): 9,000,000 milliseconds before | | | 11. | SELECT DATEADD(dayofyear, 18, '4-29-1988 10:30 AM') | | | 12. | SELECT DATEADD(quarter, 18, '4-29-1988 10:30 AM') | | | 13. | Combine the CONVERT()and the DATEADD() functions to format a return
date value nine months before September 8, 1989 | | | 14. | SELECT DATEADD(mi, -30, '2005-09-01 23:30:00.000') | | | 15. | select DATEADD(month, -1, '2002-09-30 11:35:00') | | | 16. | DATEADD: add days to a date | | | 17. | Combine DateADD and DateDIFF to get the last date of a month | | |
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