|
1>
2>
3> CREATE TABLE works_on (emp_no INTEGER NOT NULL,
4> project_no CHAR(4) NOT NULL,
5> job CHAR (15) NULL,
6> enter_date DATETIME NULL)
7> GO
1> insert into works_on values (1, 'p1', 'analyst', '1997.10.1')
2> insert into works_on values (1, 'p3', 'manager', '1999.1.1')
3> insert into works_on values (2, 'p2', 'clerk', '1998.2.15')
4> insert into works_on values (2, 'p2', NULL, '1998.6.1')
5> insert into works_on values (3, 'p2', NULL, '1997.12.15')
6> insert into works_on values (4, 'p3', 'analyst', '1998.10.15')
7> insert into works_on values (5, 'p1', 'manager', '1998.4.15')
8> insert into works_on values (6, 'p1', NULL, '1998.8.1')
9> insert into works_on values (7, 'p2', 'clerk', '1999.2.1')
10> insert into works_on values (8, 'p3', 'clerk', '1997.11.15')
11> insert into works_on values (7, 'p1', 'clerk', '1998.1.4')
12> GO
(1 rows affected)
(1 rows affected)
(1 rows affected)
(1 rows affected)
(1 rows affected)
(1 rows affected)
(1 rows affected)
(1 rows affected)
(1 rows affected)
(1 rows affected)
(1 rows affected)
1> -- HAVING clause can also be used without aggregates
2>
3> SELECT job FROM works_on GROUP BY job HAVING job LIKE 'M%'
4> GO
job
---------------
manager
(1 rows affected)
1> drop table works_on
2> GO
|