Use NOT EXISTS to represent the ALL operator : EXISTS « Select Query « SQL Server / T-SQL

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SQL Server / T-SQL » Select Query » EXISTS 
Use NOT EXISTS to represent the ALL operator


26>
27CREATE TABLE employee  (emp_no    INTEGER NOT NULL,
28>                         emp_fname CHAR(20NOT NULL,
29>                         emp_lname CHAR(20NOT NULL,
30>                         dept_no   CHAR(4NULL)
31>
32insert into employee values(1,  'Matthew', 'Smith',    'd3')
33insert into employee values(2,  'Ann',     'Jones',    'd3')
34insert into employee values(3,  'John',    'Barrimore','d1')
35insert into employee values(4,  'James',   'James',    'd2')
36insert into employee values(5,  'Elsa',    'Bertoni',  'd2')
37insert into employee values(6,  'Elke',    'Hansel',   'd2')
38insert into employee values(7,  'Sybill',  'Moser',    'd1')
39>
40select from employee
41> GO

(rows affected)

(rows affected)

(rows affected)

(rows affected)

(rows affected)

(rows affected)

(rows affected)
emp_no      emp_fname            emp_lname            dept_no
----------- -------------------- -------------------- -------
          Matthew              Smith                d3
          Ann                  Jones                d3
          John                 Barrimore            d1
          James                James                d2
          Elsa                 Bertoni              d2
          Elke                 Hansel               d2
          Sybill               Moser                d1

(rows affected)
1>
2CREATE TABLE works_on        (emp_no       INTEGER NOT NULL,
3>                         project_no    CHAR(4NOT NULL,
4>                         job CHAR (15NULL,
5>                         enter_date    DATETIME NULL)
6>
7insert into works_on values (1'p1', 'analyst', '1997.10.1')
8insert into works_on values (1'p3', 'manager', '1999.1.1')
9insert into works_on values (2'p2', 'clerk',   '1998.2.15')
10insert into works_on values (2'p2',  NULL,     '1998.6.1')
11insert into works_on values (3'p2',  NULL,     '1997.12.15')
12insert into works_on values (4'p3', 'analyst', '1998.10.15')
13insert into works_on values (5'p1', 'manager', '1998.4.15')
14insert into works_on values (6'p1',  NULL,     '1998.8.1')
15insert into works_on values (7'p2', 'clerk',   '1999.2.1')
16insert into works_on values (8'p3', 'clerk',   '1997.11.15')
17insert into works_on values (7'p1', 'clerk',   '1998.1.4')
18>
19select from works_on
20> GO

(rows affected)

(rows affected)

(rows affected)

(rows affected)

(rows affected)

(rows affected)

(rows affected)

(rows affected)

(rows affected)

(rows affected)

(rows affected)
emp_no      project_no job             enter_date
----------- ---------- --------------- -----------------------
          p1         analyst         1997-10-01 00:00:00.000
          p3         manager         1999-01-01 00:00:00.000
          p2         clerk           1998-02-15 00:00:00.000
          p2         NULL            1998-06-01 00:00:00.000
          p2         NULL            1997-12-15 00:00:00.000
          p3         analyst         1998-10-15 00:00:00.000
          p1         manager         1998-04-15 00:00:00.000
          p1         NULL            1998-08-01 00:00:00.000
          p2         clerk           1999-02-01 00:00:00.000
          p3         clerk           1997-11-15 00:00:00.000
          p1         clerk           1998-01-04 00:00:00.000

(11 rows affected)
1> --Use NOT EXISTS to represent the ALL operator.
2>
3SELECT DISTINCT job FROM works_on WHERE NOT EXISTS
4>        (SELECT FROM employee WHERE works_on.emp_no > employee.emp_no)
5> GO
job
---------------
analyst
manager

(rows affected)
1>
2> drop table works_on
3> drop table employee
4> GO
1>
2>
           
       
Related examples in the same category
1. NOT EXISTS function
2. EXISTS function can be used to represent the ANY and ALL operators
3. Checks for existing Product record
4. Using EXISTS Operator for a subquery
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