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34>
35> CREATE TABLE employee (emp_no INTEGER NOT NULL,
36> emp_fname CHAR(20) NOT NULL,
37> emp_lname CHAR(20) NOT NULL,
38> dept_no CHAR(4) NULL)
39>
40> insert into employee values(1, 'Matthew', 'Smith', 'd3')
41> insert into employee values(2, 'Ann', 'Jones', 'd3')
42> insert into employee values(3, 'John', 'Barrimore','d1')
43> insert into employee values(4, 'James', 'James', 'd2')
44> insert into employee values(5, 'Elsa', 'Bertoni', 'd2')
45> insert into employee values(6, 'Elke', 'Hansel', 'd2')
46> insert into employee values(7, 'Sybill', 'Moser', 'd1')
47>
48> select * from employee
49> GO
(1 rows affected)
(1 rows affected)
(1 rows affected)
(1 rows affected)
(1 rows affected)
(1 rows affected)
(1 rows affected)
emp_no emp_fname emp_lname dept_no
----------- -------------------- -------------------- -------
1 Matthew Smith d3
2 Ann Jones d3
3 John Barrimore d1
4 James James d2
5 Elsa Bertoni d2
6 Elke Hansel d2
7 Sybill Moser d1
(7 rows affected)
1>
2>
3> CREATE TABLE works_on (emp_no INTEGER NOT NULL,
4> project_no CHAR(4) NOT NULL,
5> job CHAR (15) NULL,
6> enter_date DATETIME NULL)
7> GO
1>
2> insert into works_on values (1, 'p1', 'analyst', '1997.10.1')
3> insert into works_on values (1, 'p3', 'manager', '1999.1.1')
4> insert into works_on values (2, 'p2', 'clerk', '1998.2.15')
5> insert into works_on values (2, 'p2', NULL, '1998.6.1')
6> insert into works_on values (3, 'p2', NULL, '1997.12.15')
7> insert into works_on values (4, 'p3', 'analyst', '1998.10.15')
8> insert into works_on values (5, 'p1', 'manager', '1998.4.15')
9> insert into works_on values (6, 'p1', NULL, '1998.8.1')
10> insert into works_on values (7, 'p2', 'clerk', '1999.2.1')
11> insert into works_on values (8, 'p3', 'clerk', '1997.11.15')
12> insert into works_on values (7, 'p1', 'clerk', '1998.1.4')
13> GO
(1 rows affected)
(1 rows affected)
(1 rows affected)
(1 rows affected)
(1 rows affected)
(1 rows affected)
(1 rows affected)
(1 rows affected)
(1 rows affected)
(1 rows affected)
(1 rows affected)
1>
2>
3> CREATE TABLE project (project_no CHAR(4) NOT NULL,
4> project_name CHAR(15) NOT NULL,
5> budget FLOAT NULL)
6> GO
1>
2> insert into project values ('p1', 'Search Engine', 120000.00)
3> insert into project values ('p2', 'Programming', 95000.00)
4> insert into project values ('p3', 'SQL', 186500.00)
5> GO
(1 rows affected)
(1 rows affected)
(1 rows affected)
1>
2> -- Nested three level subquery with in operator
3>
4> SELECT emp_lname FROM employee WHERE emp_no IN
5> (SELECT emp_no FROM works_on WHERE project_no IN
6> (SELECT project_no FROM project WHERE project_name = 'SQL'))
7> GO
emp_lname
--------------------
Smith
James
(2 rows affected)
1>
2> drop table employee
3> drop table works_on
4> drop table project
5> GO
1>
2>
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