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1>
2> create table employee(
3> ID int,
4> name nvarchar (10),
5> salary int )
6> GO
1>
2> create table job(
3> ID int,
4> title nvarchar (10),
5> averageSalary int)
6> GO
1>
2>
3> insert into employee (ID, name, salary) values (1, 'Jason', 1234)
4> GO
1> insert into employee (ID, name, salary) values (2, 'Robert', 4321)
2> GO
1> insert into employee (ID, name, salary) values (3, 'Celia', 5432)
2> GO
1> insert into employee (ID, name, salary) values (4, 'Linda', 3456)
2> GO
1> insert into employee (ID, name, salary) values (5, 'David', 7654)
2> GO
1> insert into employee (ID, name, salary) values (6, 'James', 4567)
2> GO
1> insert into employee (ID, name, salary) values (7, 'Alison', 8744)
2> GO
1> insert into employee (ID, name, salary) values (8, 'Chris', 9875)
2> GO
1> insert into employee (ID, name, salary) values (9, 'Mary', 2345)
2> GO
1>
2> insert into job(ID, title, averageSalary) values(1,'Developer',3000)
3> GO
1> insert into job(ID, title, averageSalary) values(2,'Tester', 4000)
2> GO
1> insert into job(ID, title, averageSalary) values(3,'Designer', 5000)
2> GO
1> insert into job(ID, title, averageSalary) values(4,'Programmer', 6000)
2> GO
1>
2>
3> select * from employee;
4> GO
ID name salary
----------- ---------- -----------
1 Jason 1234
2 Robert 4321
3 Celia 5432
4 Linda 3456
5 David 7654
6 James 4567
7 Alison 8744
8 Chris 9875
9 Mary 2345
1> select * from job;
2> GO
ID title averageSalary
----------- ---------- -------------
1 Developer 3000
2 Tester 4000
3 Designer 5000
4 Programmer 6000
1>
2> SELECT count(e.id)
3> FROM Employee e LEFT JOIN job j
4> ON e.ID = j.ID
5> group by j.ID
6> ORDER BY j.ID
7> GO
-----------
5
1
1
1
1
1>
2>
3>
4> drop table employee;
5> drop table job;
6> GO
1>
2>
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