Create regex to search for IP address pattern 2 : Regex IP « Regular Expression « C# / CSharp Tutorial

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C# / CSharp Tutorial » Regular Expression » Regex IP 
17.5.2.Create regex to search for IP address pattern 2
using System;
using System.Text.RegularExpressions;

public class MainClass
{
    static void Mainstring[] args ) {

        string pattern = @"([01]?\d\d?|2[0-4]\d|25[0-5])\." +
                         @"([01]?\d\d?|2[0-4]\d|25[0-5])\." +
                         @"([01]?\d\d?|2[0-4]\d|25[0-5])\." +
                         @"([01]?\d\d?|2[0-4]\d|25[0-5])";
        Regex regex = new Regexpattern );
        Match match = regex.Match"192.168.1.168" );
        whilematch.Success ) {
            Console.WriteLine"IP Address found at {0} with " +
                               "value of {1}",
                               match.Index,
                               match.Value );

            match = match.NextMatch();
        }
        
    }
}
IP Address found at 0 with value of 192.168.1.168
17.5.Regex IP
17.5.1.Create regex to search for IP address pattern
17.5.2.Create regex to search for IP address pattern 2
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