Do a replace using the Regex : Regular Expression « Regular Expression « C# / CSharp Tutorial

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C# / CSharp Tutorial » Regular Expression » Regular Expression 
17.1.2.Do a replace using the Regex
using System;
using System.Text.RegularExpressions;

public class MainClass
{
    static void Main( string[] args ) {
        // Create regex to search for IP address pattern.
        string pattern = @"([01]?\d\d?|2[0-4]\d|25[0-5])\." +
                         @"([01]?\d\d?|2[0-4]\d|25[0-5])\." +
                         @"([01]?\d\d?|2[0-4]\d|25[0-5])\." +
                         @"([01]?\d\d?|2[0-4]\d|25[0-5])";
        Regex regex = new Regex( pattern );
        Console.WriteLine( "Input given --> {0}",
                           regex.Replace("192.168.199.1",
                                         "xxx.xxx.xxx.xxx") );
    }
}
 
Input given --> xxx.xxx.xxx.xxx
17.1.Regular Expression
17.1.1.Use Regular Expressions to split string
17.1.2.Do a replace using the Regex
17.1.3.Reverse
17.1.4.Regular Expresion Part
17.1.5.new Regex('^\\d+') 1
17.1.6.new Regex('\d+$') 2
17.1.7.new Regex('^\\d+$') 3
17.1.8.new Regex('(abc)|(xyz)*') 1
17.1.9.new Regex('((abc)|(xyz))*') 2
17.1.10.new Regex('((?:abc)|(?:xyz))*') 3
17.1.11.new Regex(?(^\d)^\d+$|^\D+$)
17.1.12.new Regex((abc)*)x(\1)
17.1.13.new Regex(^\d+$\n+, RegexOptions.Multiline)
17.1.14.new Regex((abc)*abc((abcd)|z)bc)
17.1.15.new Regex(<[^>]+>[^<]*]+>): for XML tag
17.1.16.new Regex(<([^>]+)>[^<]*: for XML tag
17.1.17.Using RegEx
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