Computing an Impedance with Complex Numbers : complex number « Data Types

Computing an Impedance with Complex Numbers : complex number « Data Types « C++ Tutorial

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C++ Tutorial » Data Types » complex number

2.26.9.Computing an Impedance with Complex Numbers

#include <complex>

#include <iomanip>

#include <iostream>

#include <cmath>



using namespace std;



complex<double> parallel_RLC_impedance( double frequency, double resistance, double inductance, double capacitance );



int main( )

{

   const double R = 1000.0;   

   const double L = 0.2;      

   const double C = 10.0e-9;  

   double frequency;



   frequency = 1.0 / sqrt( L * C );



   complex<double> impedance = parallel_RLC_impedance( frequency, R, L, C );



   cout << impedance << "   Magnitude = " << abs( impedance ) << "   Phase = " << arg( impedance ) << endl;



   impedance = parallel_RLC_impedance( frequency / 10, R, L, C );



   cout << impedance << "   Magnitude = " << abs( impedance ) << "   Phase = " << arg( impedance ) << endl;



   impedance = parallel_RLC_impedance( frequency * 10, R, L, C );



   cout << impedance << "   Magnitude = " << abs( impedance ) << "   Phase = " << arg( impedance ) << endl;

}



inline

complex<double> parallel_RLC_impedance( double frequency,double resistance, double inductance, double capacitance )

{

   complex<double> impedance_inverse( 1.0 / resistance,frequency * capacitance - 1.0 / ( frequency * inductance ) );



   return 1.0 / impedance_inverse;

}

2.26.complex number
	2.26.1.	Create complex numbers based on double value
	2.26.2.	Plus two complex numbers together
	2.26.3.	Complex + integer
	2.26.4.	Use polar to create complex number
	2.26.5.	Complex number: magnitude, squared magnitude and phase angle
	2.26.6.	Complex conjugates
	2.26.7.	Complex number + float number
	2.26.8.	print sum of two complex numbers
	2.26.9.	Computing an Impedance with Complex Numbers
	2.26.10.	The << and >> operators are overloaded relative to complex numbers.
	2.26.11.	Add square root of two complex numbers and print the result

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