Output pointer value using cout : long « Data Types « C++ Tutorial

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C++ Tutorial » Data Types » long

2.12.4.Output pointer value using cout

#include <iostream>

using std::cout;

using std::endl;



int main() {

  long* pnumber;                        

  long number1 = 55L;

  long number2 = 99L;                   



  pnumber = &number1;                   

  *pnumber += 11;                       

  cout << endl

       << "number1 = "     << number1

       << "   &number1 = " << pnumber

       << endl;



  pnumber = &number2;                   

  number1 = *pnumber * 10;              



  cout << "number1 = "     << number1

       << "   pnumber = "  << pnumber

       << "   *pnumber = " << *pnumber

       << endl;



  return 0;

}

number1 = 66   &number1 = 0x22ff70
number1 = 990   pnumber = 0x22ff6c   *pnumber = 99

2.12.long
	2.12.1.	pointer to long value
	2.12.2.	Use long as function parameter and return type
	2.12.3.	Cast int to long
	2.12.4.	Output pointer value using cout

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