Pass by reference using references : reference parameter « Function « C++ Tutorial

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C++ Tutorial » Function » reference parameter

7.4.4.Pass by reference using references

#include <iostream>

 

 void swap(int &x, int &y);

 

 int main()

 {

     int x = 5, y = 10;

 

     std::cout << "Main. Before swap, x: " << x 

                                 << " y: " << y << "\n";

     swap(x,y);

     std::cout << "Main. After swap, x: " << x 

                                << " y: " << y << "\n";

     return 0;

 }

 

 void swap (int &rx, int &ry)

 {

     int temp;

 

     std::cout << "Swap. Before swap, rx: " << rx 

                                 << " ry: " << ry << "\n";

 

     temp = rx;

     rx = ry;

     ry = temp;

 

     std::cout << "Swap. After swap, rx: " << rx 

                                << " ry: " << ry << "\n";

 }

Main. Before swap, x: 5 y: 10
Swap. Before swap, rx: 5 ry: 10
Swap. After swap, rx: 10 ry: 5
Main. After swap, x: 10 y: 5

7.4.reference parameter
	7.4.1.	Using a reference parameter.
	7.4.2.	Use reference parameters to create the swap() function.
	7.4.3.	Pass by reference by using pointer
	7.4.4.	Pass by reference using references
	7.4.5.	Returning multiple values from a function using references
	7.4.6.	Passing references to objects

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