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import java.io.File;
import java.io.FileFilter;
import java.io.UnsupportedEncodingException;
import java.util.ArrayList;
import java.util.List;
import java.util.regex.Pattern;
import java.util.regex.PatternSyntaxException;
/*
* Licensed to the Apache Software Foundation (ASF) under one
* or more contributor license agreements. See the NOTICE file
* distributed with this work for additional information
* regarding copyright ownership. The ASF licenses this file
* to you under the Apache License, Version 2.0 (the
* "License"); you may not use this file except in compliance
* with the License. You may obtain a copy of the License at
*
* http://www.apache.org/licenses/LICENSE-2.0
*
* Unless required by applicable law or agreed to in writing,
* software distributed under the License is distributed on an
* "AS IS" BASIS, WITHOUT WARRANTIES OR CONDITIONS OF ANY
* KIND, either express or implied. See the License for the
* specific language governing permissions and limitations
* under the License.
*
*/
/**
* Various string manipulation methods that are more efficient then chaining
* string operations: all is done in the same buffer without creating a bunch of
* string objects.
*
* @author <a href="mailto:dev@labs.apache.org">Dungeon Project</a>
*/
public class Main {
/**
* Check if a text is present at the current position in another string.
*
* @param string
* The string which contains the data
* @param index
* Current position in the string
* @param text
* The text we want to check
* @return <code>true</code> if the string contains the text.
*/
public static final boolean areEquals( String string, int index, String text )
{
if ( ( string == null ) || ( text == null ) )
{
return false;
}
int length1 = string.length();
int length2 = text.length();
if ( ( length1 == 0 ) || ( length1 <= index ) || ( index < 0 )
|| ( text == null ) || ( length2 == 0 )
|| ( length2 > ( length1 + index ) ) )
{
return false;
}
else
{
return string.substring( index ).startsWith( text );
}
}
}
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