FLOOR for negative value : FLOOR « Numerical Math Functions « Oracle PL/SQL Tutorial

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Oracle PL/SQL Tutorial » Numerical Math Functions » FLOOR 
14. 12. 3. FLOOR for negative value
SQL>
SQL> -- create demo table
SQL> create table myTable(
  2    id           NUMBER(2),
  3    value        NUMBER(6,2)
  4  )
  5  /

Table created.

SQL>
SQL> -- prepare data
SQL> insert into myTable(ID,  value)values (1,9)
  2  /

row created.

SQL> insert into myTable(ID,  value)values (2,2.11)
  2  /

row created.

SQL> insert into myTable(ID,  value)values (3,3.44)
  2  /

row created.

SQL> insert into myTable(ID,  value)values (4,-4.21)
  2  /

row created.

SQL> insert into myTable(ID,  value)values (5,10)
  2  /

row created.

SQL> insert into myTable(ID,  value)values (6,3)
  2  /

row created.

SQL> insert into myTable(ID,  value)values (7,-5.88)
  2  /

row created.

SQL> insert into myTable(ID,  value)values (8,123.45)
  2  /

row created.

SQL> insert into myTable(ID,  value)values (9,98.23)
  2  /

row created.

SQL>
SQL> select from myTable
  2  /

        ID      VALUE
---------- ----------
         1          9
         2       2.11
         3       3.44
         4      -4.21
         5         10
         6          3
         7      -5.88
         8     123.45
         9      98.23

rows selected.

SQL>
SQL>
SQL> SELECT id, value,FLOOR(valueFROM myTable
  2  /

        ID      VALUE FLOOR(VALUE)
---------- ---------- ------------
         1          9            9
         2       2.11            2
         3       3.44            3
         4      -4.21           -5
         5         10           10
         6          3            3
         7      -5.88           -6
         8     123.45          123
         9      98.23           98

rows selected.

SQL>
SQL>
SQL>
SQL> -- clean the table
SQL> drop table myTable
  2  /

Table dropped.

SQL>
SQL>
14. 12. FLOOR
14. 12. 1. FLOOR(x) gets the largest integer less than or equal to x.
14. 12. 2. Use FLOOR function to get the flooring value
14. 12. 3. FLOOR for negative value
14. 12. 4. FLOOR(5.8)
14. 12. 5. FLOOR(-5.2)
14. 12. 6. select round(345.678), ceil(345.678), floor(345.678)
14. 12. 7. Use floor to get the number of weeks
14. 12. 8. Use floor and mod to get the number of days
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