Select distinct value from inner join : Inner join « Table Join « SQL Server / T-SQL Tutorial

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SQL Server / T-SQL Tutorial » Table Join » Inner join 
4. 3. 4. Select distinct value from inner join
3CREATE TABLE Customers (
4>      CustomerID nchar (5NOT NULL ,
5>      CompanyName nvarchar (40NOT NULL ,
6>      ContactName nvarchar (30NULL ,
7>      ContactTitle nvarchar (30NULL ,
8>      Address nvarchar (60NULL ,
9>      City nvarchar (15NULL ,
10>     Region nvarchar (15NULL ,
11>     PostalCode nvarchar (10NULL ,
12>     Country nvarchar (15NULL ,
13>     Phone nvarchar (24NULL ,
14>     Fax nvarchar (24NULL
15)
16> GO
1>
2INSERT Customers VALUES('1','A','Maria',    'Sales',  'Str. 57', 'Berlin'    ,NULL,'12209', 'Germany','111-1111111','111-1111111')
3INSERT Customers VALUES('2','M','Joe',      'Owner',  'Ave. 231','Vancouver' ,NULL,'05023', 'Mexico', '(222222-3332',NULL)
4INSERT Customers VALUES('3','H','Thomas',   'Sales',  'Sq.  111','London'    ,NULL,'1D00P', 'UK',     '(444444-4444','(444444-4444')
5INSERT Customers VALUES('4','B','Berg',     'Order',  'Blv    8','Toronto'   ,NULL,'00222', 'Sweden', '4444-55 55 65','5555-55 55 55')
6INSERT Customers VALUES('5','S','Moos',     'Sales',  'Fort  57','New York'  ,NULL,'68306', 'Germany','6666-66666','6666-77777')
7INSERT Customers VALUES('6','F','Cite',     'Manager','24      ','Dalles'    ,NULL,'67000', 'France', '88.60.15.31','88.60.15.32')
8INSERT Customers VALUES('7','C','Sommer',   'Owner',  'Araq, 67','Paris'     ,NULL,'28023', 'Spain',  '(91555 22 82','(91555 91 99')
9INSERT Customers VALUES('8','P','Leb',      'Owner',  '12      ','Beijing'   ,NULL,'13008', 'France', '91.24.45.40','91.24.45.41')
10INSERT Customers VALUES('9','D','Elizabeth','Manager','23 Blvd.','Tsawassen','BC', 'T2F8M4','Canada', '(604555-4729','(604555-3745')
11> go

(rows affected)

(rows affected)

(rows affected)

(rows affected)

(rows affected)

(rows affected)

(rows affected)

(rows affected)

(rows affected)
1>
2>
3CREATE TABLE Orders (
4>      OrderID int NOT NULL ,
5>      CustomerID nchar (5NULL ,
6>      EmployeeID int NULL ,
7>      OrderDate datetime NULL ,
8>      RequiredDate datetime NULL ,
9>      ShippedDate datetime NULL ,
10>     ShipVia int NULL ,
11>     Freight money NULL DEFAULT (0),
12>     ShipName nvarchar (40NULL ,
13>     ShipAddress nvarchar (60NULL ,
14>     ShipCity nvarchar (15NULL ,
15>     ShipRegion nvarchar (15NULL ,
16>     ShipPostalCode nvarchar (10NULL ,
17>     ShipCountry nvarchar (15NULL
18)
19> GO
1>
2>
3INSERT INTO Orders VALUES (10248,'1',5,'7/4/1996','8/1/2001','7/16/2001',3,32.38,'V','A','R',        NULL,N'51100','France')
7> go
1>
2>
3>    SELECT DISTINCT c.CustomerID, c.CompanyName
4>    FROM Customers c
5>    INNER JOIN Orders o
6>            ON c.CustomerID = o.CustomerID
7> GO
CustomerID CompanyName
---------- ----------------------------------------

(rows affected)
1>
2> drop table orders;
3> drop table customers;
4> GO
4. 3. Inner join
4. 3. 1. The explicit syntax for an inner join
4. 3. 2. The syntax for an inner join that uses correlation names
4. 3. 3. An inner join with correlation names that make the query more difficult to read
4. 3. 4. Select distinct value from inner join
4. 3. 5. Inner join two table with column in common
4. 3. 6. Inner join with where clause
4. 3. 7. Once you decide to alias a table, you must use that alias in every part of the query.
4. 3. 8. works with the qualified * operator
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