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SQL> CREATE TABLE employee(
2 employee_id INTEGER,
3 division_id CHAR(3),
4 job_id CHAR(3),
5 first_name VARCHAR2(10) NOT NULL,
6 last_name VARCHAR2(10) NOT NULL,
7 salary NUMBER(6, 0)
8 );
Table created.
SQL>
SQL> insert into employee (EMPLOYEE_ID,division_id,JOB_ID,FIRST_NAME,LAST_NAME,SALARY)
2 values(1, 'BUS','PRE','James','Smith','800000');
1 row created.
SQL> insert into employee (EMPLOYEE_ID,division_id,JOB_ID,FIRST_NAME,LAST_NAME,SALARY)
2 values(2, 'SAL','MGR','Ron','Johnson','350000');
1 row created.
SQL> insert into employee (EMPLOYEE_ID,division_id,JOB_ID,FIRST_NAME,LAST_NAME,SALARY)
2 values(3, 'SAL','WOR','Fred','Hobbs','140000');
1 row created.
SQL> insert into employee (EMPLOYEE_ID,division_id,JOB_ID,FIRST_NAME,LAST_NAME,SALARY)
2 values(4, 'SUP','MGR','Susan','Jones','200000');
1 row created.
SQL> insert into employee (EMPLOYEE_ID,division_id,JOB_ID,FIRST_NAME,LAST_NAME,SALARY)
2 values(5, 'SAL','WOR','Rob','Green','350000');
1 row created.
SQL>
SQL> select * from employee;
EMPLOYEE_ID DIV JOB FIRST_NAME LAST_NAME SALARY
----------- --- --- ---------- ---------- ----------
1 BUS PRE James Smith 800000
2 SAL MGR Ron Johnson 350000
3 SAL WOR Fred Hobbs 140000
4 SUP MGR Susan Jones 200000
5 SAL WOR Rob Green 350000
SQL>
SQL>
SQL>
SQL>
SQL> --A Useful Application of GROUPING_ID()
SQL>
SQL> --One useful application of GROUPING_ID() is to filter rows using a HAVING clause.
Your HAVING clause can exclude rows that don’t contain a subtotal or total by simply checking
if GROUPING_ID() returns a value greater than 0. For example:
SQL>
SQL> SELECT
2 division_id, job_id,
3 GROUPING_ID(division_id, job_id) AS grp_id,
4 SUM(salary)
5 FROM employee
6 GROUP BY CUBE(division_id, job_id)
7 HAVING GROUPING_ID(division_id, job_id) > 0;
DIV JOB GRP_ID SUM(SALARY)
--- --- ---------- -----------
3 1840000
MGR 2 550000
PRE 2 800000
WOR 2 490000
BUS 1 800000
SAL 1 840000
SUP 1 200000
7 rows selected.
SQL>
SQL>
SQL>
SQL>
SQL> drop table employee;
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