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SQL> CREATE TABLE employee(
2 employee_id INTEGER,
3 division_id CHAR(3),
4 job_id CHAR(3),
5 first_name VARCHAR2(10) NOT NULL,
6 last_name VARCHAR2(10) NOT NULL,
7 salary NUMBER(6, 0)
8 );
Table created.
SQL>
SQL> insert into employee (EMPLOYEE_ID,division_id,JOB_ID,FIRST_NAME,LAST_NAME,SALARY)
2 values(1, 'BUS','PRE','James','Smith','800000');
1 row created.
SQL> insert into employee (EMPLOYEE_ID,division_id,JOB_ID,FIRST_NAME,LAST_NAME,SALARY)
2 values(2, 'SAL','MGR','Ron','Johnson','350000');
1 row created.
SQL> insert into employee (EMPLOYEE_ID,division_id,JOB_ID,FIRST_NAME,LAST_NAME,SALARY)
2 values(3, 'SAL','WOR','Fred','Hobbs','140000');
1 row created.
SQL> insert into employee (EMPLOYEE_ID,division_id,JOB_ID,FIRST_NAME,LAST_NAME,SALARY)
2 values(4, 'SUP','MGR','Susan','Jones','200000');
1 row created.
SQL> insert into employee (EMPLOYEE_ID,division_id,JOB_ID,FIRST_NAME,LAST_NAME,SALARY)
2 values(5, 'SAL','WOR','Rob','Green','350000');
1 row created.
SQL>
SQL> select * from employee;
EMPLOYEE_ID DIV JOB FIRST_NAME LAST_NAME SALARY
----------- --- --- ---------- ---------- ----------
1 BUS PRE James Smith 800000
2 SAL MGR Ron Johnson 350000
3 SAL WOR Fred Hobbs 140000
4 SUP MGR Susan Jones 200000
5 SAL WOR Rob Green 350000
SQL>
SQL> --Using the GROUP_ID() Function
SQL>
SQL> --You can use the GROUP_ID() function to remove duplicate rows returned by a GROUP BY clause.
GROUP_ID() doesn’t accept any parameters.
If n duplicates exist for a particular grouping, GROUP_ID returns numbers in the range 0 to n-1.
SQL>
SQL>
SQL> SELECT division_id, job_id, GROUP_ID(), SUM(salary)
2 FROM employee
3 GROUP BY division_id, ROLLUP(division_id, job_id);
DIV JOB GROUP_ID() SUM(SALARY)
--- --- ---------- -----------
BUS PRE 0 800000
SAL MGR 0 350000
SAL WOR 0 490000
SUP MGR 0 200000
BUS 0 800000
SAL 0 840000
SUP 0 200000
BUS 1 800000
SAL 1 840000
SUP 1 200000
10 rows selected.
SQL>
SQL>
SQL>
SQL> drop table employee;
Table dropped.
SQL>
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