DateDiff("m", "3/15/2000", Now) : DateDiff « Date Functions « VBA / Excel / Access / Word

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VBA / Excel / Access / Word » Date Functions » DateDiff

DateDiff("m", "3/15/2000", Now)


 

Sub dateFunctions1()

   Debug.Print "The months between 3/15/2000 and today is: " & DateDiff("m", "3/15/2000", Now)

End Sub

Related examples in the same category

1.	DateDiff(interval, date1, date2[, firstdayofweek[, firstweekofyear]]) returns the interval between two specified dates
2.	DateDiff returns the interval of time between two dates:
3.	Difference between two dates in days and months:
4.	returns the number of weeks between June 3, 2006 and September 30, 2006:
5.	DateDiff() function returns the difference between two dates. The unit for the difference is specified as a string ( "s" for second, "m" for month, "yyyy" for year, and so on).
6.	DateDiff("m", Now, "10/10/03")
7.	DateDiff("yyyy", Now, "10/10/03")
8.	Use DateDiff function

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