returns the number of weeks between June 3, 2006 and September 30, 2006: : DateDiff « Date Functions « VBA / Excel / Access / Word

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VBA / Excel / Access / Word » Date Functions » DateDiff 
returns the number of weeks between June 3, 2006 and September 30, 2006:
 
Sub dateD()
    MsgBox DateDiff("ww""6/3/2006""9/30/2006")
End Sub
'Using the Dir Function to Check Whether a File Exists
  Sub Does_File_Exist()
      Dim strTestFile As String, strNameToTest As String
      strNameToTest = "c:\"
      If strNameToTest = "" Then End
      strTestFile = Dir(strNameToTest)
      If Len(strTestFile) = 0 Then
          Debug.Print "The file " & strNameToTest & " does not exist."
      Else
          Debug.Print "The file " & strNameToTest & " exists."
      End If
  End Sub

 
Related examples in the same category
1. DateDiff(interval, date1, date2[, firstdayofweek[, firstweekofyear]]) returns the interval between two specified dates
2. DateDiff returns the interval of time between two dates:
3. Difference between two dates in days and months:
4. DateDiff() function returns the difference between two dates. The unit for the difference is specified as a string ( "s" for second, "m" for month, "yyyy" for year, and so on).
5. DateDiff("m", Now, "10/10/03")
6. DateDiff("yyyy", Now, "10/10/03")
7. DateDiff("m", "3/15/2000", Now)
8. Use DateDiff function
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